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2641735849057 is a prime number
BaseRepresentation
bin100110011100010011101…
…110100001010001100001
3100100112210010001201012121
4212130103232201101201
5321240233334132212
65341332515224241
7361600451135224
oct46342356412141
910315703051177
102641735849057
11929399020518
12367b9bba8081
13162164a92a46
1491c09a795bb
1548ab6e17d07
hex26713ba1461

2641735849057 has 2 divisors, whose sum is σ = 2641735849058. Its totient is φ = 2641735849056.

The previous prime is 2641735849033. The next prime is 2641735849061. The reversal of 2641735849057 is 7509485371462.

It is a strong prime.

It can be written as a sum of positive squares in only one way, i.e., 2485743237376 + 155992611681 = 1576624^2 + 394959^2 .

It is a cyclic number.

It is not a de Polignac number, because 2641735849057 - 215 = 2641735816289 is a prime.

It is a junction number, because it is equal to n+sod(n) for n = 2641735848986 and 2641735849004.

It is not a weakly prime, because it can be changed into another prime (2641735849457) by changing a digit.

It is a pernicious number, because its binary representation contains a prime number (19) of ones.

It is a polite number, since it can be written as a sum of consecutive naturals, namely, 1320867924528 + 1320867924529.

It is an arithmetic number, because the mean of its divisors is an integer number (1320867924529).

It is a 1-persistent number, because it is pandigital, but 2⋅2641735849057 = 5283471698114 is not.

Almost surely, 22641735849057 is an apocalyptic number.

It is an amenable number.

2641735849057 is a deficient number, since it is larger than the sum of its proper divisors (1).

2641735849057 is an equidigital number, since it uses as much as digits as its factorization.

2641735849057 is an odious number, because the sum of its binary digits is odd.

The product of its (nonzero) digits is 50803200, while the sum is 61.

The spelling of 2641735849057 in words is "two trillion, six hundred forty-one billion, seven hundred thirty-five million, eight hundred forty-nine thousand, fifty-seven".