Base | Representation |
---|---|
bin | 1100000001001010110011… |
… | …11001011111111011111011 |
3 | 10110120112102120020121202111 |
4 | 12000211121321133323323 |
5 | 11431000422124030111 |
6 | 132113020400313151 |
7 | 5365251300423031 |
oct | 600453171377373 |
9 | 113515376217674 |
10 | 26428442017531 |
11 | 846a26a5925a4 |
12 | 2b6a0139127b7 |
13 | 1199264633128 |
14 | 675201780551 |
15 | 30c6e7691a21 |
hex | 180959e5fefb |
26428442017531 has 2 divisors, whose sum is σ = 26428442017532. Its totient is φ = 26428442017530.
The previous prime is 26428442017501. The next prime is 26428442017583. The reversal of 26428442017531 is 13571024482462.
It is a weak prime.
It is a cyclic number.
It is not a de Polignac number, because 26428442017531 - 211 = 26428442015483 is a prime.
It is a super-2 number, since 2×264284420175312 (a number of 28 digits) contains 22 as substring.
It is not a weakly prime, because it can be changed into another prime (26428442017501) by changing a digit.
It is a polite number, since it can be written as a sum of consecutive naturals, namely, 13214221008765 + 13214221008766.
It is an arithmetic number, because the mean of its divisors is an integer number (13214221008766).
Almost surely, 226428442017531 is an apocalyptic number.
26428442017531 is a deficient number, since it is larger than the sum of its proper divisors (1).
26428442017531 is an equidigital number, since it uses as much as digits as its factorization.
26428442017531 is an odious number, because the sum of its binary digits is odd.
The product of its (nonzero) digits is 2580480, while the sum is 49.
Adding to 26428442017531 its reverse (13571024482462), we get a palindrome (39999466499993).
The spelling of 26428442017531 in words is "twenty-six trillion, four hundred twenty-eight billion, four hundred forty-two million, seventeen thousand, five hundred thirty-one".
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