Base | Representation |
---|---|
bin | 111100001000000111100010… |
… | …001101001000100010111001 |
3 | 1021200022021111122002211012212 |
4 | 330020013202031020202321 |
5 | 234130043410423303423 |
6 | 2334230203520144505 |
7 | 106462130330261234 |
oct | 7410074215104271 |
9 | 1250267448084185 |
10 | 264440636541113 |
11 | 7729370a41319a |
12 | 257aa44a168135 |
13 | b472850177616 |
14 | 4942dd07a641b |
15 | 2088a93d17578 |
hex | f081e23488b9 |
264440636541113 has 2 divisors, whose sum is σ = 264440636541114. Its totient is φ = 264440636541112.
The previous prime is 264440636541017. The next prime is 264440636541139. The reversal of 264440636541113 is 311145636044462.
It is a strong prime.
It can be written as a sum of positive squares in only one way, i.e., 216554416460944 + 47886220080169 = 14715788^2 + 6919987^2 .
It is a cyclic number.
It is not a de Polignac number, because 264440636541113 - 222 = 264440632346809 is a prime.
It is not a weakly prime, because it can be changed into another prime (264440636546113) by changing a digit.
It is a polite number, since it can be written as a sum of consecutive naturals, namely, 132220318270556 + 132220318270557.
It is an arithmetic number, because the mean of its divisors is an integer number (132220318270557).
Almost surely, 2264440636541113 is an apocalyptic number.
It is an amenable number.
264440636541113 is a deficient number, since it is larger than the sum of its proper divisors (1).
264440636541113 is an equidigital number, since it uses as much as digits as its factorization.
264440636541113 is an evil number, because the sum of its binary digits is even.
The product of its (nonzero) digits is 4976640, while the sum is 50.
The spelling of 264440636541113 in words is "two hundred sixty-four trillion, four hundred forty billion, six hundred thirty-six million, five hundred forty-one thousand, one hundred thirteen".
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