Base | Representation |
---|---|
bin | 1111011010100110111… |
… | …0010001110011000001 |
3 | 221022121012002122211220 |
4 | 3312221232101303001 |
5 | 13314343131023311 |
6 | 321355510425253 |
7 | 25063664663013 |
oct | 3665156216301 |
9 | 838535078756 |
10 | 264840486081 |
11 | a2355606086 |
12 | 433b2662229 |
13 | 1bc888577c2 |
14 | cb657921b3 |
15 | 6d50b20206 |
hex | 3da9b91cc1 |
264840486081 has 4 divisors (see below), whose sum is σ = 353120648112. Its totient is φ = 176560324052.
The previous prime is 264840486077. The next prime is 264840486083. The reversal of 264840486081 is 180684048462.
It is a semiprime because it is the product of two primes, and also a Blum integer, because the two primes are equal to 3 mod 4.
It is a cyclic number.
It is not a de Polignac number, because 264840486081 - 22 = 264840486077 is a prime.
It is a super-2 number, since 2×2648404860812 (a number of 24 digits) contains 22 as substring.
It is not an unprimeable number, because it can be changed into a prime (264840486083) by changing a digit.
It is a polite number, since it can be written in 3 ways as a sum of consecutive naturals, for example, 44140081011 + ... + 44140081016.
It is an arithmetic number, because the mean of its divisors is an integer number (88280162028).
Almost surely, 2264840486081 is an apocalyptic number.
It is an amenable number.
264840486081 is a deficient number, since it is larger than the sum of its proper divisors (88280162031).
264840486081 is an equidigital number, since it uses as much as digits as its factorization.
264840486081 is an evil number, because the sum of its binary digits is even.
The sum of its prime factors is 88280162030.
The product of its (nonzero) digits is 2359296, while the sum is 51.
The spelling of 264840486081 in words is "two hundred sixty-four billion, eight hundred forty million, four hundred eighty-six thousand, eighty-one".
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