Search a number
-
+
2651601411001 = 22311890589287
BaseRepresentation
bin100110100101011111110…
…000101001101110111001
3100101111020122212011222201
4212211133300221232321
5321420434430123001
65350043500350201
7362400104053414
oct46453760515671
910344218764881
102651601411001
119325a09621a4
12369a93b45361
1316307796c66a
14924a4004b7b
1548e930bc501
hex2695fc29bb9

2651601411001 has 4 divisors (see below), whose sum is σ = 2663492000512. Its totient is φ = 2639710821492.

The previous prime is 2651601410917. The next prime is 2651601411029. The reversal of 2651601411001 is 1001141061562.

It is a semiprime because it is the product of two primes, and also a Blum integer, because the two primes are equal to 3 mod 4.

It is a cyclic number.

It is not a de Polignac number, because 2651601411001 - 213 = 2651601402809 is a prime.

It is a Duffinian number.

It is not an unprimeable number, because it can be changed into a prime (2651601411031) by changing a digit.

It is a polite number, since it can be written in 3 ways as a sum of consecutive naturals, for example, 5945294421 + ... + 5945294866.

It is an arithmetic number, because the mean of its divisors is an integer number (665873000128).

Almost surely, 22651601411001 is an apocalyptic number.

It is an amenable number.

2651601411001 is a deficient number, since it is larger than the sum of its proper divisors (11890589511).

2651601411001 is a wasteful number, since it uses less digits than its factorization.

2651601411001 is an evil number, because the sum of its binary digits is even.

The sum of its prime factors is 11890589510.

The product of its (nonzero) digits is 1440, while the sum is 28.

Adding to 2651601411001 its reverse (1001141061562), we get a palindrome (3652742472563).

The spelling of 2651601411001 in words is "two trillion, six hundred fifty-one billion, six hundred one million, four hundred eleven thousand, one".

Divisors: 1 223 11890589287 2651601411001