Base | Representation |
---|---|
bin | 100110110000000111011… |
… | …010111011111110011001 |
3 | 100102120200100021011202011 |
4 | 212300013122323332121 |
5 | 322112313040203213 |
6 | 5355211154305521 |
7 | 363252504302356 |
oct | 46600732737631 |
9 | 10376610234664 |
10 | 2663004225433 |
11 | 937412508482 |
12 | 3701368882a1 |
13 | 164174182636 |
14 | 92c665ad62d |
15 | 4940e1c903d |
hex | 26c076bbf99 |
2663004225433 has 2 divisors, whose sum is σ = 2663004225434. Its totient is φ = 2663004225432.
The previous prime is 2663004225319. The next prime is 2663004225463. The reversal of 2663004225433 is 3345224003662.
It is a strong prime.
It can be written as a sum of positive squares in only one way, i.e., 2332364275264 + 330639950169 = 1527208^2 + 575013^2 .
It is a cyclic number.
It is not a de Polignac number, because 2663004225433 - 29 = 2663004224921 is a prime.
It is not a weakly prime, because it can be changed into another prime (2663004225463) by changing a digit.
It is a polite number, since it can be written as a sum of consecutive naturals, namely, 1331502112716 + 1331502112717.
It is an arithmetic number, because the mean of its divisors is an integer number (1331502112717).
Almost surely, 22663004225433 is an apocalyptic number.
It is an amenable number.
2663004225433 is a deficient number, since it is larger than the sum of its proper divisors (1).
2663004225433 is an equidigital number, since it uses as much as digits as its factorization.
2663004225433 is an evil number, because the sum of its binary digits is even.
The product of its (nonzero) digits is 622080, while the sum is 40.
The spelling of 2663004225433 in words is "two trillion, six hundred sixty-three billion, four million, two hundred twenty-five thousand, four hundred thirty-three".
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