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2665140120147 = 31877473297837
BaseRepresentation
bin100110110010000110101…
…110101110101001010011
3100102210012012022212110210
4212302012232232221103
5322131201332321042
65400203134055203
7363356441145561
oct46620656565123
910383165285423
102665140120147
1193830913281a
1237063204a503
1316442482a56b
1492dca120a31
15494d6981a9c
hex26c86baea53

2665140120147 has 8 divisors (see below), whose sum is σ = 3555413359056. Its totient is φ = 1775813480672.

The previous prime is 2665140120127. The next prime is 2665140120151. The reversal of 2665140120147 is 7410210415662.

2665140120147 is digitally balanced in base 3, because in such base it contains all the possibile digits an equal number of times.

It is a sphenic number, since it is the product of 3 distinct primes.

It is a cyclic number.

It is not a de Polignac number, because 2665140120147 - 28 = 2665140119891 is a prime.

It is not an unprimeable number, because it can be changed into a prime (2665140120127) by changing a digit.

It is a polite number, since it can be written in 7 ways as a sum of consecutive naturals, for example, 236643288 + ... + 236654549.

It is an arithmetic number, because the mean of its divisors is an integer number (444426669882).

Almost surely, 22665140120147 is an apocalyptic number.

2665140120147 is a deficient number, since it is larger than the sum of its proper divisors (890273238909).

2665140120147 is a wasteful number, since it uses less digits than its factorization.

2665140120147 is an evil number, because the sum of its binary digits is even.

The sum of its prime factors is 473299717.

The product of its (nonzero) digits is 80640, while the sum is 39.

The spelling of 2665140120147 in words is "two trillion, six hundred sixty-five billion, one hundred forty million, one hundred twenty thousand, one hundred forty-seven".

Divisors: 1 3 1877 5631 473297837 1419893511 888380040049 2665140120147