Search a number
-
+
266716525793 is a prime number
BaseRepresentation
bin1111100001100110001…
…0110011010011100001
3221111102221012100112012
43320121202303103201
513332213412311133
6322310004442305
725161325030364
oct3703142632341
9844387170465
10266716525793
11a3128586523
12438369a9395
131c1c741c483
14cca29c00db
156e10698b48
hex3e198b34e1

266716525793 has 2 divisors, whose sum is σ = 266716525794. Its totient is φ = 266716525792.

The previous prime is 266716525771. The next prime is 266716525813. The reversal of 266716525793 is 397525617662.

266716525793 is digitally balanced in base 2, because in such base it contains all the possibile digits an equal number of times.

It is a strong prime.

It can be written as a sum of positive squares in only one way, i.e., 231675680929 + 35040844864 = 481327^2 + 187192^2 .

It is a cyclic number.

It is a de Polignac number, because none of the positive numbers 2k-266716525793 is a prime.

It is a super-2 number, since 2×2667165257932 (a number of 24 digits) contains 22 as substring.

It is not a weakly prime, because it can be changed into another prime (266716545793) by changing a digit.

It is a pernicious number, because its binary representation contains a prime number (19) of ones.

It is a polite number, since it can be written as a sum of consecutive naturals, namely, 133358262896 + 133358262897.

It is an arithmetic number, because the mean of its divisors is an integer number (133358262897).

Almost surely, 2266716525793 is an apocalyptic number.

It is an amenable number.

266716525793 is a deficient number, since it is larger than the sum of its proper divisors (1).

266716525793 is an equidigital number, since it uses as much as digits as its factorization.

266716525793 is an odious number, because the sum of its binary digits is odd.

The product of its digits is 28576800, while the sum is 59.

The spelling of 266716525793 in words is "two hundred sixty-six billion, seven hundred sixteen million, five hundred twenty-five thousand, seven hundred ninety-three".