Base | Representation |
---|---|
bin | 100110111001110011111… |
… | …010111000100110000001 |
3 | 100110120112211222121021002 |
4 | 212321303322320212001 |
5 | 322300123101132423 |
6 | 5404052154141345 |
7 | 364101463042535 |
oct | 46716372704601 |
9 | 10416484877232 |
10 | 2673414474113 |
11 | 940874858389 |
12 | 372161121855 |
13 | 165142b5c1b6 |
14 | 93573003bc5 |
15 | 4981d0c2228 |
hex | 26e73eb8981 |
2673414474113 has 2 divisors, whose sum is σ = 2673414474114. Its totient is φ = 2673414474112.
The previous prime is 2673414474089. The next prime is 2673414474119. The reversal of 2673414474113 is 3114744143762.
It is a strong prime.
It can be written as a sum of positive squares in only one way, i.e., 1729887823504 + 943526650609 = 1315252^2 + 971353^2 .
It is a cyclic number.
It is not a de Polignac number, because 2673414474113 - 210 = 2673414473089 is a prime.
It is not a weakly prime, because it can be changed into another prime (2673414474119) by changing a digit.
It is a polite number, since it can be written as a sum of consecutive naturals, namely, 1336707237056 + 1336707237057.
It is an arithmetic number, because the mean of its divisors is an integer number (1336707237057).
Almost surely, 22673414474113 is an apocalyptic number.
It is an amenable number.
2673414474113 is a deficient number, since it is larger than the sum of its proper divisors (1).
2673414474113 is an equidigital number, since it uses as much as digits as its factorization.
2673414474113 is an evil number, because the sum of its binary digits is even.
The product of its digits is 1354752, while the sum is 47.
The spelling of 2673414474113 in words is "two trillion, six hundred seventy-three billion, four hundred fourteen million, four hundred seventy-four thousand, one hundred thirteen".
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