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274112841311657 is a prime number
BaseRepresentation
bin111110010100110111011110…
…100010001110010110101001
31022221112221011012210002112022
4332110313132202032112221
5241412031044333433112
62410553411215554225
7111510666512312615
oct7624673642162651
91287487135702468
10274112841311657
117a38266a8a46a7
12268b0aa3b2b975
13b9c4964b20cba
144b991bd0a8345
1521a54862d2d72
hexf94dde88e5a9

274112841311657 has 2 divisors, whose sum is σ = 274112841311658. Its totient is φ = 274112841311656.

The previous prime is 274112841311471. The next prime is 274112841311669. The reversal of 274112841311657 is 756113148211472.

It is a strong prime.

It can be written as a sum of positive squares in only one way, i.e., 268980369185641 + 5132472126016 = 16400621^2 + 2265496^2 .

It is a cyclic number.

It is not a de Polignac number, because 274112841311657 - 28 = 274112841311401 is a prime.

It is a junction number, because it is equal to n+sod(n) for n = 274112841311599 and 274112841311608.

It is not a weakly prime, because it can be changed into another prime (274112841310657) by changing a digit.

It is a polite number, since it can be written as a sum of consecutive naturals, namely, 137056420655828 + 137056420655829.

It is an arithmetic number, because the mean of its divisors is an integer number (137056420655829).

Almost surely, 2274112841311657 is an apocalyptic number.

It is an amenable number.

274112841311657 is a deficient number, since it is larger than the sum of its proper divisors (1).

274112841311657 is an equidigital number, since it uses as much as digits as its factorization.

274112841311657 is an odious number, because the sum of its binary digits is odd.

The product of its digits is 2257920, while the sum is 53.

The spelling of 274112841311657 in words is "two hundred seventy-four trillion, one hundred twelve billion, eight hundred forty-one million, three hundred eleven thousand, six hundred fifty-seven".