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28052525005003 = 47596862234149
BaseRepresentation
bin1100110000011011111001…
…10010011011100011001011
310200022210110200220121211201
412120031330302123203023
512134103032400130003
6135355052503205031
75623504502145412
oct630157462334313
9120283420817751
1028052525005003
118a36011045a14
123190925a46777
131286459ac05c5
146cda6c70a479
15339a9d1aab1d
hex19837cc9b8cb

28052525005003 has 4 divisors (see below), whose sum is σ = 28649387239200. Its totient is φ = 27455662770808.

The previous prime is 28052525004971. The next prime is 28052525005009. The reversal of 28052525005003 is 30050052525082.

It is a semiprime because it is the product of two primes.

It is a cyclic number.

It is not a de Polignac number, because 28052525005003 - 25 = 28052525004971 is a prime.

It is a Duffinian number.

It is not an unprimeable number, because it can be changed into a prime (28052525005009) by changing a digit.

It is a polite number, since it can be written in 3 ways as a sum of consecutive naturals, for example, 298431117028 + ... + 298431117121.

It is an arithmetic number, because the mean of its divisors is an integer number (7162346809800).

Almost surely, 228052525005003 is an apocalyptic number.

28052525005003 is a deficient number, since it is larger than the sum of its proper divisors (596862234197).

28052525005003 is an equidigital number, since it uses as much as digits as its factorization.

28052525005003 is an evil number, because the sum of its binary digits is even.

The sum of its prime factors is 596862234196.

The product of its (nonzero) digits is 120000, while the sum is 37.

The spelling of 28052525005003 in words is "twenty-eight trillion, fifty-two billion, five hundred twenty-five million, five thousand, three".

Divisors: 1 47 596862234149 28052525005003