Base | Representation |
---|---|
bin | 1100110000011011111001… |
… | …10010011011100011001011 |
3 | 10200022210110200220121211201 |
4 | 12120031330302123203023 |
5 | 12134103032400130003 |
6 | 135355052503205031 |
7 | 5623504502145412 |
oct | 630157462334313 |
9 | 120283420817751 |
10 | 28052525005003 |
11 | 8a36011045a14 |
12 | 3190925a46777 |
13 | 1286459ac05c5 |
14 | 6cda6c70a479 |
15 | 339a9d1aab1d |
hex | 19837cc9b8cb |
28052525005003 has 4 divisors (see below), whose sum is σ = 28649387239200. Its totient is φ = 27455662770808.
The previous prime is 28052525004971. The next prime is 28052525005009. The reversal of 28052525005003 is 30050052525082.
It is a semiprime because it is the product of two primes.
It is a cyclic number.
It is not a de Polignac number, because 28052525005003 - 25 = 28052525004971 is a prime.
It is a Duffinian number.
It is not an unprimeable number, because it can be changed into a prime (28052525005009) by changing a digit.
It is a polite number, since it can be written in 3 ways as a sum of consecutive naturals, for example, 298431117028 + ... + 298431117121.
It is an arithmetic number, because the mean of its divisors is an integer number (7162346809800).
Almost surely, 228052525005003 is an apocalyptic number.
28052525005003 is a deficient number, since it is larger than the sum of its proper divisors (596862234197).
28052525005003 is an equidigital number, since it uses as much as digits as its factorization.
28052525005003 is an evil number, because the sum of its binary digits is even.
The sum of its prime factors is 596862234196.
The product of its (nonzero) digits is 120000, while the sum is 37.
The spelling of 28052525005003 in words is "twenty-eight trillion, fifty-two billion, five hundred twenty-five million, five thousand, three".
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