Base | Representation |
---|---|
bin | 110101101001… |
… | …0100011011011 |
3 | 1221220220210121 |
4 | 1223102203123 |
5 | 24200003103 |
6 | 2442454111 |
7 | 461030155 |
oct | 153224333 |
9 | 57826717 |
10 | 28125403 |
11 | 14970039 |
12 | 9504337 |
13 | 5a99967 |
14 | 3a41ad5 |
15 | 27086bd |
hex | 1ad28db |
28125403 has 2 divisors, whose sum is σ = 28125404. Its totient is φ = 28125402.
The previous prime is 28125353. The next prime is 28125407. The reversal of 28125403 is 30452182.
It is a strong prime.
It is a cyclic number.
It is not a de Polignac number, because 28125403 - 29 = 28124891 is a prime.
It is not a weakly prime, because it can be changed into another prime (28125407) by changing a digit.
It is a polite number, since it can be written as a sum of consecutive naturals, namely, 14062701 + 14062702.
It is an arithmetic number, because the mean of its divisors is an integer number (14062702).
Almost surely, 228125403 is an apocalyptic number.
28125403 is a deficient number, since it is larger than the sum of its proper divisors (1).
28125403 is an equidigital number, since it uses as much as digits as its factorization.
28125403 is an evil number, because the sum of its binary digits is even.
The product of its (nonzero) digits is 1920, while the sum is 25.
The square root of 28125403 is about 5303.3388539674. The cubic root of 28125403 is about 304.1115522917. Note that the first 3 decimals are identical.
Adding to 28125403 its reverse (30452182), we get a palindrome (58577585).
The spelling of 28125403 in words is "twenty-eight million, one hundred twenty-five thousand, four hundred three".
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