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28131425433 = 3219316195409
BaseRepresentation
bin11010001100110000…
…110111110010011001
32200121112020110221200
4122030300313302121
5430103121103213
620531242024413
72014060112406
oct321460676231
980545213850
1028131425433
1110a26502331
1255511a8109
132864215287
14150c2012ad
15ae9a77273
hex68cc37c99

28131425433 has 12 divisors (see below), whose sum is σ = 40844824020. Its totient is φ = 18657110016.

The previous prime is 28131425431. The next prime is 28131425459. The reversal of 28131425433 is 33452413182.

28131425433 is a `hidden beast` number, since 2 + 81 + 3 + 142 + 5 + 433 = 666.

It can be written as a sum of positive squares in 2 ways, for example, as 5957832969 + 22173592464 = 77187^2 + 148908^2 .

It is not a de Polignac number, because 28131425433 - 21 = 28131425431 is a prime.

It is not an unprimeable number, because it can be changed into a prime (28131425431) by changing a digit.

It is a polite number, since it can be written in 11 ways as a sum of consecutive naturals, for example, 8095968 + ... + 8099441.

It is an arithmetic number, because the mean of its divisors is an integer number (3403735335).

Almost surely, 228131425433 is an apocalyptic number.

It is an amenable number.

28131425433 is a deficient number, since it is larger than the sum of its proper divisors (12713398587).

28131425433 is a wasteful number, since it uses less digits than its factorization.

28131425433 is an evil number, because the sum of its binary digits is even.

The sum of its prime factors is 16195608 (or 16195605 counting only the distinct ones).

The product of its digits is 69120, while the sum is 36.

The spelling of 28131425433 in words is "twenty-eight billion, one hundred thirty-one million, four hundred twenty-five thousand, four hundred thirty-three".

Divisors: 1 3 9 193 579 1737 16195409 48586227 145758681 3125713937 9377141811 28131425433