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2816654490113 is a prime number
BaseRepresentation
bin101000111111001101101…
…100001011101000000001
3100222021021111100100101212
4220333031230023220001
5332122002022140423
65553541520535505
7410332216064612
oct50771554135001
910867244310355
102816654490113
1199659a0364a2
12395a77a81595
131757bca60909
149a480a75c09
154d403498578
hex28fcdb0ba01

2816654490113 has 2 divisors, whose sum is σ = 2816654490114. Its totient is φ = 2816654490112.

The previous prime is 2816654490037. The next prime is 2816654490149. The reversal of 2816654490113 is 3110944566182.

It is a strong prime.

It can be written as a sum of positive squares in only one way, i.e., 2103825508849 + 712828981264 = 1450457^2 + 844292^2 .

It is a cyclic number.

It is not a de Polignac number, because 2816654490113 - 214 = 2816654473729 is a prime.

It is a Sophie Germain prime.

It is a Curzon number.

It is not a weakly prime, because it can be changed into another prime (2816654490413) by changing a digit.

It is a polite number, since it can be written as a sum of consecutive naturals, namely, 1408327245056 + 1408327245057.

It is an arithmetic number, because the mean of its divisors is an integer number (1408327245057).

Almost surely, 22816654490113 is an apocalyptic number.

It is an amenable number.

2816654490113 is a deficient number, since it is larger than the sum of its proper divisors (1).

2816654490113 is an equidigital number, since it uses as much as digits as its factorization.

2816654490113 is an evil number, because the sum of its binary digits is even.

The product of its (nonzero) digits is 1244160, while the sum is 50.

The spelling of 2816654490113 in words is "two trillion, eight hundred sixteen billion, six hundred fifty-four million, four hundred ninety thousand, one hundred thirteen".