Base | Representation |
---|---|
bin | 11010010111000011… |
… | …011110110101010001 |
3 | 2201001120010001011022 |
4 | 122113003132311101 |
5 | 430431320413423 |
6 | 21000330325225 |
7 | 2021254451225 |
oct | 322703366521 |
9 | 81046101138 |
10 | 28304076113 |
11 | 11004a05345 |
12 | 559ab89815 |
13 | 2890c14c41 |
14 | 1527104785 |
15 | b09cccdc8 |
hex | 6970ded51 |
28304076113 has 2 divisors, whose sum is σ = 28304076114. Its totient is φ = 28304076112.
The previous prime is 28304076071. The next prime is 28304076127. The reversal of 28304076113 is 31167040382.
It is a strong prime.
It can be written as a sum of positive squares in only one way, i.e., 27731574784 + 572501329 = 166528^2 + 23927^2 .
It is a cyclic number.
It is not a de Polignac number, because 28304076113 - 210 = 28304075089 is a prime.
It is a super-2 number, since 2×283040761132 (a number of 22 digits) contains 22 as substring.
It is not a weakly prime, because it can be changed into another prime (28304076193) by changing a digit.
It is a pernicious number, because its binary representation contains a prime number (19) of ones.
It is a polite number, since it can be written as a sum of consecutive naturals, namely, 14152038056 + 14152038057.
It is an arithmetic number, because the mean of its divisors is an integer number (14152038057).
Almost surely, 228304076113 is an apocalyptic number.
It is an amenable number.
28304076113 is a deficient number, since it is larger than the sum of its proper divisors (1).
28304076113 is an equidigital number, since it uses as much as digits as its factorization.
28304076113 is an odious number, because the sum of its binary digits is odd.
The product of its (nonzero) digits is 24192, while the sum is 35.
The spelling of 28304076113 in words is "twenty-eight billion, three hundred four million, seventy-six thousand, one hundred thirteen".
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