287640113 has 2 divisors, whose sum is σ = 287640114. Its totient is φ = 287640112.

The previous prime is 287640097. The next prime is 287640121. The reversal of 287640113 is 311046782.

287640113 = 11992² + 11993².

It is a strong prime.

It can be written as a sum of positive squares in only one way, i.e., 143832049 + 143808064 = 11993^2 + 11992^2 .

It is a cyclic number.

It is not a de Polignac number, because 287640113 - 2⁴ = 287640097 is a prime.

It is a Sophie Germain prime.

It is a Curzon number.

It is a self number, because there is not a number n which added to its sum of digits gives 287640113.

It is not a weakly prime, because it can be changed into another prime (287640173) by changing a digit.

It is a polite number, since it can be written as a sum of consecutive naturals, namely, 143820056 + 143820057.

It is an arithmetic number, because the mean of its divisors is an integer number (143820057).

Almost surely, 2^287640113 is an apocalyptic number.

287640113 is the 11993-rd centered square number.

It is an amenable number.

287640113 is a deficient number, since it is larger than the sum of its proper divisors (1).

287640113 is an equidigital number, since it uses as much as digits as its factorization.

287640113 is an evil number, because the sum of its binary digits is even.

The product of its (nonzero) digits is 8064, while the sum is 32.

The square root of 287640113 is about 16959.9561614999. The cubic root of 287640113 is about 660.1102608868.

Adding to 287640113 its reverse (311046782), we get a palindrome (598686895).

The spelling of 287640113 in words is "two hundred eighty-seven million, six hundred forty thousand, one hundred thirteen".