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2923004916473 is a prime number
BaseRepresentation
bin101010100010010000101…
…010110111001011111001
3101100102210020102202220212
4222202100222313023321
5340342303224311343
610114450535400505
7421115533562645
oct52422052671371
911312706382825
102923004916473
11a27704088944
123b25b8523135
1318283b111395
14a168d283c25
1551079e8ac18
hex2a890ab72f9

2923004916473 has 2 divisors, whose sum is σ = 2923004916474. Its totient is φ = 2923004916472.

The previous prime is 2923004916443. The next prime is 2923004916497. The reversal of 2923004916473 is 3746194003292.

2923004916473 is digitally balanced in base 2, because in such base it contains all the possibile digits an equal number of times.

It is a strong prime.

It can be written as a sum of positive squares in only one way, i.e., 2283081714169 + 639923202304 = 1510987^2 + 799952^2 .

It is a cyclic number.

It is not a de Polignac number, because 2923004916473 - 26 = 2923004916409 is a prime.

It is not a weakly prime, because it can be changed into another prime (2923004916443) by changing a digit.

It is a polite number, since it can be written as a sum of consecutive naturals, namely, 1461502458236 + 1461502458237.

It is an arithmetic number, because the mean of its divisors is an integer number (1461502458237).

Almost surely, 22923004916473 is an apocalyptic number.

It is an amenable number.

2923004916473 is a deficient number, since it is larger than the sum of its proper divisors (1).

2923004916473 is an equidigital number, since it uses as much as digits as its factorization.

2923004916473 is an odious number, because the sum of its binary digits is odd.

The product of its (nonzero) digits is 1959552, while the sum is 50.

The spelling of 2923004916473 in words is "two trillion, nine hundred twenty-three billion, four million, nine hundred sixteen thousand, four hundred seventy-three".