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29234145002947 is a prime number
BaseRepresentation
bin1101010010110100110101…
…10101000000010111000011
310211111202102211101212222021
412221122122311000113003
512312433012110043242
6142101551504422311
76105045236334553
oct651323265002703
9124452384355867
1029234145002947
1193511497a3465
123341934017997
1313409ca518941
14730d23b6b163
1535a6a9479b67
hex1a969ad405c3

29234145002947 has 2 divisors, whose sum is σ = 29234145002948. Its totient is φ = 29234145002946.

The previous prime is 29234145002879. The next prime is 29234145003001. The reversal of 29234145002947 is 74920054143292.

It is a strong prime.

It is a cyclic number.

It is not a de Polignac number, because 29234145002947 - 227 = 29234010785219 is a prime.

It is a junction number, because it is equal to n+sod(n) for n = 29234145002894 and 29234145002903.

It is not a weakly prime, because it can be changed into another prime (29234145032947) by changing a digit.

It is a polite number, since it can be written as a sum of consecutive naturals, namely, 14617072501473 + 14617072501474.

It is an arithmetic number, because the mean of its divisors is an integer number (14617072501474).

Almost surely, 229234145002947 is an apocalyptic number.

29234145002947 is a deficient number, since it is larger than the sum of its proper divisors (1).

29234145002947 is an equidigital number, since it uses as much as digits as its factorization.

29234145002947 is an odious number, because the sum of its binary digits is odd.

The product of its (nonzero) digits is 4354560, while the sum is 52.

The spelling of 29234145002947 in words is "twenty-nine trillion, two hundred thirty-four billion, one hundred forty-five million, two thousand, nine hundred forty-seven".