Base | Representation |
---|---|
bin | 1101010110101110011011… |
… | …10110011010001011111011 |
3 | 10211222120022112000210020101 |
4 | 12223113031312122023323 |
5 | 12322131430104320232 |
6 | 142243312313340231 |
7 | 6120531003433534 |
oct | 653271566321373 |
9 | 124876275023211 |
10 | 29368144995067 |
11 | 93a2a622508aa |
12 | 33638b0407677 |
13 | 135053400b3c8 |
14 | 7375d658768b |
15 | 35dded5611e7 |
hex | 1ab5cdd9a2fb |
29368144995067 has 2 divisors, whose sum is σ = 29368144995068. Its totient is φ = 29368144995066.
The previous prime is 29368144995019. The next prime is 29368144995089. The reversal of 29368144995067 is 76059944186392.
It is a strong prime.
It is a cyclic number.
It is not a de Polignac number, because 29368144995067 - 27 = 29368144994939 is a prime.
It is not a weakly prime, because it can be changed into another prime (29368144993067) by changing a digit.
It is a polite number, since it can be written as a sum of consecutive naturals, namely, 14684072497533 + 14684072497534.
It is an arithmetic number, because the mean of its divisors is an integer number (14684072497534).
It is a 2-persistent number, because it is pandigital, and so is 2⋅29368144995067 = 58736289990134, but 3⋅29368144995067 = 88104434985201 is not.
Almost surely, 229368144995067 is an apocalyptic number.
29368144995067 is a deficient number, since it is larger than the sum of its proper divisors (1).
29368144995067 is an equidigital number, since it uses as much as digits as its factorization.
29368144995067 is an evil number, because the sum of its binary digits is even.
The product of its (nonzero) digits is 705438720, while the sum is 73.
The spelling of 29368144995067 in words is "twenty-nine trillion, three hundred sixty-eight billion, one hundred forty-four million, nine hundred ninety-five thousand, sixty-seven".
• e-mail: info -at- numbersaplenty.com • Privacy notice • done in 0.093 sec. • engine limits •