Base | Representation |
---|---|
bin | 101010110001100110010… |
… | …110010010011111010001 |
3 | 101102000022001022222022201 |
4 | 222301212112102133101 |
5 | 341130021013440033 |
6 | 10130213121203201 |
7 | 422240632054360 |
oct | 52614626223721 |
9 | 11360261288281 |
10 | 2939474749393 |
11 | a33695956106 |
12 | 3b5834190501 |
13 | 184264319650 |
14 | a23b27977d7 |
15 | 516e0d3b47d |
hex | 2ac665927d1 |
2939474749393 has 16 divisors (see below), whose sum is σ = 3625731571840. Its totient is φ = 2320649087616.
The previous prime is 2939474749373. The next prime is 2939474749411. The reversal of 2939474749393 is 3939474749392.
2939474749393 is digitally balanced in base 2, because in such base it contains all the possibile digits an equal number of times.
It is a cyclic number.
It is not a de Polignac number, because 2939474749393 - 233 = 2930884814801 is a prime.
It is not an unprimeable number, because it can be changed into a prime (2939474749363) by changing a digit.
It is a polite number, since it can be written in 15 ways as a sum of consecutive naturals, for example, 35299683 + ... + 35382856.
It is an arithmetic number, because the mean of its divisors is an integer number (226608223240).
Almost surely, 22939474749393 is an apocalyptic number.
It is an amenable number.
2939474749393 is a deficient number, since it is larger than the sum of its proper divisors (686256822447).
2939474749393 is a wasteful number, since it uses less digits than its factorization.
2939474749393 is an odious number, because the sum of its binary digits is odd.
The sum of its prime factors is 70683016.
The product of its digits is 1111065984, while the sum is 73.
Subtracting 2939474749393 from its reverse (3939474749392), we obtain a palindrome (999999999999).
The spelling of 2939474749393 in words is "two trillion, nine hundred thirty-nine billion, four hundred seventy-four million, seven hundred forty-nine thousand, three hundred ninety-three".
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