Base | Representation |
---|---|
bin | 101010110010001100110… |
… | …000101101101111110001 |
3 | 101102001221222000000102212 |
4 | 222302030300231233301 |
5 | 341132331004222433 |
6 | 10130401102221505 |
7 | 422262615643226 |
oct | 52621460555761 |
9 | 11361858000385 |
10 | 2940119210993 |
11 | a339967116a8 |
12 | 3b5993b84895 |
13 | 1843379b1783 |
14 | a24341d594d |
15 | 5172c6dcd48 |
hex | 2ac8cc2dbf1 |
2940119210993 has 2 divisors, whose sum is σ = 2940119210994. Its totient is φ = 2940119210992.
The previous prime is 2940119210957. The next prime is 2940119211013. The reversal of 2940119210993 is 3990129110492.
It is a strong prime.
It can be written as a sum of positive squares in only one way, i.e., 1578470602384 + 1361648608609 = 1256372^2 + 1166897^2 .
It is a cyclic number.
It is not a de Polignac number, because 2940119210993 - 222 = 2940115016689 is a prime.
It is a Sophie Germain prime.
It is a Curzon number.
It is not a weakly prime, because it can be changed into another prime (2940119210933) by changing a digit.
It is a polite number, since it can be written as a sum of consecutive naturals, namely, 1470059605496 + 1470059605497.
It is an arithmetic number, because the mean of its divisors is an integer number (1470059605497).
Almost surely, 22940119210993 is an apocalyptic number.
It is an amenable number.
2940119210993 is a deficient number, since it is larger than the sum of its proper divisors (1).
2940119210993 is an equidigital number, since it uses as much as digits as its factorization.
2940119210993 is an evil number, because the sum of its binary digits is even.
The product of its (nonzero) digits is 314928, while the sum is 50.
The spelling of 2940119210993 in words is "two trillion, nine hundred forty billion, one hundred nineteen million, two hundred ten thousand, nine hundred ninety-three".
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