Base | Representation |
---|---|
bin | 1101011011101111011100… |
… | …01111000110100010010011 |
3 | 10212121001011022222022120201 |
4 | 12231313232033012202103 |
5 | 12332442404134442211 |
6 | 142454413513320031 |
7 | 6136141543530562 |
oct | 655675617064223 |
9 | 125531138868521 |
10 | 29540487030931 |
11 | 945a0608a01a8 |
12 | 3391189406017 |
13 | 136386b237a16 |
14 | 741aa52b1bd9 |
15 | 3636387d30c1 |
hex | 1addee3c6893 |
29540487030931 has 2 divisors, whose sum is σ = 29540487030932. Its totient is φ = 29540487030930.
The previous prime is 29540487030907. The next prime is 29540487030961. The reversal of 29540487030931 is 13903078404592.
It is a weak prime.
It is a cyclic number.
It is not a de Polignac number, because 29540487030931 - 29 = 29540487030419 is a prime.
It is a super-3 number, since 3×295404870309313 (a number of 41 digits) contains 333 as substring. Note that it is a super-d number also for d = 2.
It is not a weakly prime, because it can be changed into another prime (29540487030961) by changing a digit.
It is a polite number, since it can be written as a sum of consecutive naturals, namely, 14770243515465 + 14770243515466.
It is an arithmetic number, because the mean of its divisors is an integer number (14770243515466).
Almost surely, 229540487030931 is an apocalyptic number.
29540487030931 is a deficient number, since it is larger than the sum of its proper divisors (1).
29540487030931 is an equidigital number, since it uses as much as digits as its factorization.
29540487030931 is an evil number, because the sum of its binary digits is even.
The product of its (nonzero) digits is 6531840, while the sum is 55.
The spelling of 29540487030931 in words is "twenty-nine trillion, five hundred forty billion, four hundred eighty-seven million, thirty thousand, nine hundred thirty-one".
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