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300011142002133 = 32921491160458049
BaseRepresentation
bin100010000110110111100100…
…1100011000011010111010101
31110100020210012022120221101210
41010031233021203003113111
5303310340304323032013
62542023114352012033
7120123042530102232
oct10415571143032725
91410223168527353
10300011142002133
1187658013427651
1229794204531019
13cb52c1088aba3
14541288c50c789
1524a3ea1aeccc3
hex110dbc98c35d5

300011142002133 has 16 divisors (see below), whose sum is σ = 413827729272000. Its totient is φ = 193101633285120.

The previous prime is 300011142002129. The next prime is 300011142002141. The reversal of 300011142002133 is 331200241110003.

It is not a de Polignac number, because 300011142002133 - 22 = 300011142002129 is a prime.

It is a Curzon number.

It is a congruent number.

It is not an unprimeable number, because it can be changed into a prime (300011142000133) by changing a digit.

It is a polite number, since it can be written in 15 ways as a sum of consecutive naturals, for example, 78359308 + ... + 82098741.

It is an arithmetic number, because the mean of its divisors is an integer number (25864233079500).

Almost surely, 2300011142002133 is an apocalyptic number.

It is an amenable number.

300011142002133 is a deficient number, since it is larger than the sum of its proper divisors (113816587269867).

300011142002133 is a wasteful number, since it uses less digits than its factorization.

300011142002133 is an evil number, because the sum of its binary digits is even.

The sum of its prime factors is 160479572.

The product of its (nonzero) digits is 432, while the sum is 21.

Adding to 300011142002133 its reverse (331200241110003), we get a palindrome (631211383112136).

The spelling of 300011142002133 in words is "three hundred trillion, eleven billion, one hundred forty-two million, two thousand, one hundred thirty-three".

Divisors: 1 3 29 87 21491 64473 623239 1869717 160458049 481374147 4653283421 13959850263 3448403931059 10345211793177 100003714000711 300011142002133