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300013229489 is a prime number
BaseRepresentation
bin1000101110110100010…
…11101001010110110001
31001200101102211011012012
410113122023221112301
514403411341320424
6345454004412305
730450415242311
oct4273213512661
91050342734165
10300013229489
11106264712866
124a1899a7095
13223a27b13cc
1410740bc7441
157c0d923b0e
hex45da2e95b1

300013229489 has 2 divisors, whose sum is σ = 300013229490. Its totient is φ = 300013229488.

The previous prime is 300013229401. The next prime is 300013229501. The reversal of 300013229489 is 984922310003.

It is a strong prime.

It can be written as a sum of positive squares in only one way, i.e., 276576069025 + 23437160464 = 525905^2 + 153092^2 .

It is a cyclic number.

It is not a de Polignac number, because 300013229489 - 220 = 300012180913 is a prime.

It is a super-2 number, since 2×3000132294892 (a number of 24 digits) contains 22 as substring.

It is not a weakly prime, because it can be changed into another prime (300013220489) by changing a digit.

It is a polite number, since it can be written as a sum of consecutive naturals, namely, 150006614744 + 150006614745.

It is an arithmetic number, because the mean of its divisors is an integer number (150006614745).

Almost surely, 2300013229489 is an apocalyptic number.

It is an amenable number.

300013229489 is a deficient number, since it is larger than the sum of its proper divisors (1).

300013229489 is an equidigital number, since it uses as much as digits as its factorization.

300013229489 is an evil number, because the sum of its binary digits is even.

The product of its (nonzero) digits is 93312, while the sum is 41.

The spelling of 300013229489 in words is "three hundred billion, thirteen million, two hundred twenty-nine thousand, four hundred eighty-nine".