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300014340413441 is a prime number
BaseRepresentation
bin100010000110111001000100…
…0001100000001100000000001
31110100021002110012222001212212
41010031302020030001200001
5303310413332121212231
62542024404005031505
7120123215015124443
oct10415621014014001
91410232405861785
10300014340413441
1187659404895385
12297949576b5595
13cb533003c1564
145412ab3202493
1524a40dc7d542b
hex110dc88301801

300014340413441 has 2 divisors, whose sum is σ = 300014340413442. Its totient is φ = 300014340413440.

The previous prime is 300014340413399. The next prime is 300014340413527. The reversal of 300014340413441 is 144314043410003.

It is a weak prime.

It can be written as a sum of positive squares in only one way, i.e., 228962927773441 + 71051412640000 = 15131521^2 + 8429200^2 .

It is a cyclic number.

It is not a de Polignac number, because 300014340413441 - 246 = 229645596235777 is a prime.

It is a junction number, because it is equal to n+sod(n) for n = 300014340413398 and 300014340413407.

It is not a weakly prime, because it can be changed into another prime (300014340413341) by changing a digit.

It is a polite number, since it can be written as a sum of consecutive naturals, namely, 150007170206720 + 150007170206721.

It is an arithmetic number, because the mean of its divisors is an integer number (150007170206721).

Almost surely, 2300014340413441 is an apocalyptic number.

It is an amenable number.

300014340413441 is a deficient number, since it is larger than the sum of its proper divisors (1).

300014340413441 is an equidigital number, since it uses as much as digits as its factorization.

300014340413441 is an evil number, because the sum of its binary digits is even.

The product of its (nonzero) digits is 27648, while the sum is 32.

Adding to 300014340413441 its reverse (144314043410003), we get a palindrome (444328383823444).

The spelling of 300014340413441 in words is "three hundred trillion, fourteen billion, three hundred forty million, four hundred thirteen thousand, four hundred forty-one".