Search a number
-
+
300014441121 = 3100004813707
BaseRepresentation
bin1000101110110100100…
…00010001001010100001
31001200101112002201020110
410113122100101022201
514403412144103441
6345454050401533
730450431446623
oct4273220211241
91050345081213
10300014441121
1110626537010a
124a18a2902a9
13223a2b16a55
1410741020c13
157c0dab2b16
hex45da4112a1

300014441121 has 4 divisors (see below), whose sum is σ = 400019254832. Its totient is φ = 200009627412.

The previous prime is 300014441101. The next prime is 300014441123. The reversal of 300014441121 is 121144410003.

It is a semiprime because it is the product of two primes, and also a Blum integer, because the two primes are equal to 3 mod 4.

It is not a de Polignac number, because 300014441121 - 27 = 300014440993 is a prime.

It is a super-2 number, since 2×3000144411212 (a number of 24 digits) contains 22 as substring.

It is a Duffinian number.

It is not an unprimeable number, because it can be changed into a prime (300014441123) by changing a digit.

It is a polite number, since it can be written in 3 ways as a sum of consecutive naturals, for example, 50002406851 + ... + 50002406856.

It is an arithmetic number, because the mean of its divisors is an integer number (100004813708).

Almost surely, 2300014441121 is an apocalyptic number.

It is an amenable number.

300014441121 is a deficient number, since it is larger than the sum of its proper divisors (100004813711).

300014441121 is a wasteful number, since it uses less digits than its factorization.

300014441121 is an odious number, because the sum of its binary digits is odd.

The sum of its prime factors is 100004813710.

The product of its (nonzero) digits is 384, while the sum is 21.

Adding to 300014441121 its reverse (121144410003), we get a palindrome (421158851124).

The spelling of 300014441121 in words is "three hundred billion, fourteen million, four hundred forty-one thousand, one hundred twenty-one".

Divisors: 1 3 100004813707 300014441121