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30002100433 = 144139208147
BaseRepresentation
bin11011111100010000…
…111011100011010001
32212102220020121121221
4123330100323203101
5442421014203213
621441025045041
72111323434364
oct337420734321
985386217557
1030002100433
11117a6449128
125993786781
132aa194c166
1416488340db
15ba8de138d
hex6fc43b8d1

30002100433 has 4 divisors (see below), whose sum is σ = 30002452720. Its totient is φ = 30001748148.

The previous prime is 30002100407. The next prime is 30002100437. The reversal of 30002100433 is 33400120003.

It is a semiprime because it is the product of two primes, and also a Blum integer, because the two primes are equal to 3 mod 4, and also a brilliant number, because the two primes have the same length.

It is a cyclic number.

It is a de Polignac number, because none of the positive numbers 2k-30002100433 is a prime.

It is a Duffinian number.

It is not an unprimeable number, because it can be changed into a prime (30002100437) by changing a digit.

It is a pernicious number, because its binary representation contains a prime number (19) of ones.

It is a polite number, since it can be written in 3 ways as a sum of consecutive naturals, for example, 40066 + ... + 248212.

It is an arithmetic number, because the mean of its divisors is an integer number (7500613180).

Almost surely, 230002100433 is an apocalyptic number.

It is an amenable number.

30002100433 is a deficient number, since it is larger than the sum of its proper divisors (352287).

30002100433 is a wasteful number, since it uses less digits than its factorization.

30002100433 is an odious number, because the sum of its binary digits is odd.

The sum of its prime factors is 352286.

The product of its (nonzero) digits is 216, while the sum is 16.

Adding to 30002100433 its reverse (33400120003), we get a palindrome (63402220436).

The spelling of 30002100433 in words is "thirty billion, two million, one hundred thousand, four hundred thirty-three".

Divisors: 1 144139 208147 30002100433