Base | Representation |
---|---|
bin | 1101101001001101100000… |
… | …00010111011110110011011 |
3 | 10221020021202120110022211021 |
4 | 12310212300002323312123 |
5 | 12413033224312401021 |
6 | 143451154212143311 |
7 | 6214444514100166 |
oct | 664466002736633 |
9 | 127207676408737 |
10 | 30003300122011 |
11 | 9618367809617 |
12 | 3446a10607b37 |
13 | 13983b7064c78 |
14 | 75a24b798add |
15 | 3706c48a2c41 |
hex | 1b49b00bbd9b |
30003300122011 has 4 divisors (see below), whose sum is σ = 30003815550312. Its totient is φ = 30002784693712.
The previous prime is 30003300121987. The next prime is 30003300122071. The reversal of 30003300122011 is 11022100330003.
It is a semiprime because it is the product of two primes.
It is a cyclic number.
It is not a de Polignac number, because 30003300122011 - 213 = 30003300113819 is a prime.
It is a super-2 number, since 2×300033001220112 (a number of 28 digits) contains 22 as substring.
It is a Duffinian number.
It is not an unprimeable number, because it can be changed into a prime (30003300122071) by changing a digit.
It is a polite number, since it can be written in 3 ways as a sum of consecutive naturals, for example, 257626825 + ... + 257743258.
It is an arithmetic number, because the mean of its divisors is an integer number (7500953887578).
Almost surely, 230003300122011 is an apocalyptic number.
30003300122011 is a deficient number, since it is larger than the sum of its proper divisors (515428301).
30003300122011 is an equidigital number, since it uses as much as digits as its factorization.
30003300122011 is an evil number, because the sum of its binary digits is even.
The sum of its prime factors is 515428300.
The product of its (nonzero) digits is 108, while the sum is 16.
Adding to 30003300122011 its reverse (11022100330003), we get a palindrome (41025400452014).
The spelling of 30003300122011 in words is "thirty trillion, three billion, three hundred million, one hundred twenty-two thousand, eleven".
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