Base | Representation |
---|---|
bin | 101011101101101101110… |
… | …011101111101100001011 |
3 | 101122011220121221001101121 |
4 | 223231231303233230023 |
5 | 343204220222434011 |
6 | 10220010232500111 |
7 | 430014345162226 |
oct | 53555563575413 |
9 | 11564817831347 |
10 | 3004024421131 |
11 | a58aaa51a958 |
12 | 40624984a637 |
13 | 18a380522196 |
14 | a55775a65bd |
15 | 5321cbdee71 |
hex | 2bb6dcefb0b |
3004024421131 has 2 divisors, whose sum is σ = 3004024421132. Its totient is φ = 3004024421130.
The previous prime is 3004024421119. The next prime is 3004024421141. The reversal of 3004024421131 is 1311244204003.
It is a strong prime.
It is a cyclic number.
It is not a de Polignac number, because 3004024421131 - 231 = 3001876937483 is a prime.
It is a super-2 number, since 2×30040244211312 (a number of 26 digits) contains 22 as substring.
It is a junction number, because it is equal to n+sod(n) for n = 3004024421096 and 3004024421105.
It is not a weakly prime, because it can be changed into another prime (3004024421141) by changing a digit.
It is a polite number, since it can be written as a sum of consecutive naturals, namely, 1502012210565 + 1502012210566.
It is an arithmetic number, because the mean of its divisors is an integer number (1502012210566).
Almost surely, 23004024421131 is an apocalyptic number.
3004024421131 is a deficient number, since it is larger than the sum of its proper divisors (1).
3004024421131 is an equidigital number, since it uses as much as digits as its factorization.
3004024421131 is an odious number, because the sum of its binary digits is odd.
The product of its (nonzero) digits is 2304, while the sum is 25.
Adding to 3004024421131 its reverse (1311244204003), we get a palindrome (4315268625134).
The spelling of 3004024421131 in words is "three trillion, four billion, twenty-four million, four hundred twenty-one thousand, one hundred thirty-one".
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