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30101547433 = 487380316253
BaseRepresentation
bin11100000010001100…
…010010100110101001
32212200211101001021011
4130002030102212221
5443121444004213
621454540343521
72113641634336
oct340214224651
985624331234
1030101547433
11118475a2131
125a00b44ba1
132ab942b039
141657b1d98d
15bb29d703d
hex7023129a9

30101547433 has 8 divisors (see below), whose sum is σ = 30173145408. Its totient is φ = 30029990544.

The previous prime is 30101547419. The next prime is 30101547521. The reversal of 30101547433 is 33474510103.

It is a sphenic number, since it is the product of 3 distinct primes.

It is a cyclic number.

It is not a de Polignac number, because 30101547433 - 229 = 29564676521 is a prime.

It is a super-2 number, since 2×301015474332 (a number of 22 digits) contains 22 as substring.

It is a Duffinian number.

It is a junction number, because it is equal to n+sod(n) for n = 30101547395 and 30101547404.

It is not an unprimeable number, because it can be changed into a prime (30101547733) by changing a digit.

It is a polite number, since it can be written in 7 ways as a sum of consecutive naturals, for example, 1843935 + ... + 1860187.

It is an arithmetic number, because the mean of its divisors is an integer number (3771643176).

Almost surely, 230101547433 is an apocalyptic number.

It is an amenable number.

30101547433 is a deficient number, since it is larger than the sum of its proper divisors (71597975).

30101547433 is a wasteful number, since it uses less digits than its factorization.

30101547433 is an evil number, because the sum of its binary digits is even.

The sum of its prime factors is 20543.

The product of its (nonzero) digits is 15120, while the sum is 31.

The spelling of 30101547433 in words is "thirty billion, one hundred one million, five hundred forty-seven thousand, four hundred thirty-three".

Divisors: 1 487 3803 16253 1852061 7915211 61810159 30101547433