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3010212113113 is a prime number
BaseRepresentation
bin101011110011011110100…
…111111010101011011001
3101122202212212011101001201
4223303132213322223121
5343304403300104423
610222512232314201
7430323601533442
oct53633647725331
911582785141051
103010212113113
11a60695297487
12407495b42961
1318ab28455c9a
14a59a32b22c9
15534810502ad
hex2bcde9faad9

3010212113113 has 2 divisors, whose sum is σ = 3010212113114. Its totient is φ = 3010212113112.

The previous prime is 3010212113093. The next prime is 3010212113131. The reversal of 3010212113113 is 3113112120103.

Together with next prime (3010212113131) it forms an Ormiston pair, because they use the same digits, order apart.

It is a strong prime.

It can be written as a sum of positive squares in only one way, i.e., 2651790778624 + 358421334489 = 1628432^2 + 598683^2 .

It is a cyclic number.

It is not a de Polignac number, because 3010212113113 - 241 = 811188857561 is a prime.

It is a super-2 number, since 2×30102121131132 (a number of 26 digits) contains 22 as substring.

It is not a weakly prime, because it can be changed into another prime (3010212713113) by changing a digit.

It is a polite number, since it can be written as a sum of consecutive naturals, namely, 1505106056556 + 1505106056557.

It is an arithmetic number, because the mean of its divisors is an integer number (1505106056557).

Almost surely, 23010212113113 is an apocalyptic number.

It is an amenable number.

3010212113113 is a deficient number, since it is larger than the sum of its proper divisors (1).

3010212113113 is an equidigital number, since it uses as much as digits as its factorization.

3010212113113 is an odious number, because the sum of its binary digits is odd.

The product of its (nonzero) digits is 108, while the sum is 19.

Adding to 3010212113113 its reverse (3113112120103), we get a palindrome (6123324233216).

The spelling of 3010212113113 in words is "three trillion, ten billion, two hundred twelve million, one hundred thirteen thousand, one hundred thirteen".