Base | Representation |
---|---|
bin | 101011110100010100010… |
… | …001110111001011110001 |
3 | 101122212012121000200002211 |
4 | 223310110101313023301 |
5 | 343313224222120142 |
6 | 10223141430412121 |
7 | 430355112155002 |
oct | 53642421671361 |
9 | 11585177020084 |
10 | 3011112301297 |
11 | a61007438161 |
12 | 4076a7501041 |
13 | 18ac3cab7209 |
14 | a5a4aa7b1a9 |
15 | 534d50b7917 |
hex | 2bd144772f1 |
3011112301297 has 2 divisors, whose sum is σ = 3011112301298. Its totient is φ = 3011112301296.
The previous prime is 3011112301273. The next prime is 3011112301367. The reversal of 3011112301297 is 7921032111103.
3011112301297 is digitally balanced in base 3, because in such base it contains all the possibile digits an equal number of times.
It is a weak prime.
It can be written as a sum of positive squares in only one way, i.e., 2395140045376 + 615972255921 = 1547624^2 + 784839^2 .
It is a cyclic number.
It is not a de Polignac number, because 3011112301297 - 239 = 2461356487409 is a prime.
It is not a weakly prime, because it can be changed into another prime (3011112301207) by changing a digit.
It is a polite number, since it can be written as a sum of consecutive naturals, namely, 1505556150648 + 1505556150649.
It is an arithmetic number, because the mean of its divisors is an integer number (1505556150649).
Almost surely, 23011112301297 is an apocalyptic number.
It is an amenable number.
3011112301297 is a deficient number, since it is larger than the sum of its proper divisors (1).
3011112301297 is an equidigital number, since it uses as much as digits as its factorization.
3011112301297 is an evil number, because the sum of its binary digits is even.
The product of its (nonzero) digits is 2268, while the sum is 31.
The spelling of 3011112301297 in words is "three trillion, eleven billion, one hundred twelve million, three hundred one thousand, two hundred ninety-seven".
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