Search a number
-
+
30111211131 = 310037070377
BaseRepresentation
bin11100000010110001…
…001001111001111011
32212201111120000100220
4130002301021321323
5443131432224011
621455523431123
72114120033361
oct340261117173
985644500326
1030111211131
1111851aa2661
125a042254a3
132abb4327c1
141659117631
15bb3795506
hex702c49e7b

30111211131 has 4 divisors (see below), whose sum is σ = 40148281512. Its totient is φ = 20074140752.

The previous prime is 30111211079. The next prime is 30111211157. The reversal of 30111211131 is 13111211103.

It is a semiprime because it is the product of two primes.

It is a cyclic number.

It is not a de Polignac number, because 30111211131 - 217 = 30111080059 is a prime.

It is a super-2 number, since 2×301112111312 (a number of 22 digits) contains 22 as substring.

It is a self number, because there is not a number n which added to its sum of digits gives 30111211131.

It is not an unprimeable number, because it can be changed into a prime (30111211831) by changing a digit.

It is a polite number, since it can be written in 3 ways as a sum of consecutive naturals, for example, 5018535186 + ... + 5018535191.

It is an arithmetic number, because the mean of its divisors is an integer number (10037070378).

Almost surely, 230111211131 is an apocalyptic number.

30111211131 is a deficient number, since it is larger than the sum of its proper divisors (10037070381).

30111211131 is a wasteful number, since it uses less digits than its factorization.

30111211131 is an evil number, because the sum of its binary digits is even.

The sum of its prime factors is 10037070380.

The product of its (nonzero) digits is 18, while the sum is 15.

Adding to 30111211131 its reverse (13111211103), we get a palindrome (43222422234).

The spelling of 30111211131 in words is "thirty billion, one hundred eleven million, two hundred eleven thousand, one hundred thirty-one".

Divisors: 1 3 10037070377 30111211131