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30113102083 is a prime number
BaseRepresentation
bin11100000010111000…
…010111100100000011
32212201122010002021011
4130002320113210003
5443132423231313
621500032141351
72114142100351
oct340270274403
985648102234
1030113102083
1111853074329
125a04997857
132abb9453cc
14165948a7d1
15bb3a1a93d
hex702e17903

30113102083 has 2 divisors, whose sum is σ = 30113102084. Its totient is φ = 30113102082.

The previous prime is 30113102011. The next prime is 30113102101. The reversal of 30113102083 is 38020131103.

It is a strong prime.

It is an emirp because it is prime and its reverse (38020131103) is a distict prime.

It is a cyclic number.

It is not a de Polignac number, because 30113102083 - 213 = 30113093891 is a prime.

It is a super-2 number, since 2×301131020832 (a number of 22 digits) contains 22 as substring.

It is not a weakly prime, because it can be changed into another prime (30113102483) by changing a digit.

It is a polite number, since it can be written as a sum of consecutive naturals, namely, 15056551041 + 15056551042.

It is an arithmetic number, because the mean of its divisors is an integer number (15056551042).

Almost surely, 230113102083 is an apocalyptic number.

30113102083 is a deficient number, since it is larger than the sum of its proper divisors (1).

30113102083 is an equidigital number, since it uses as much as digits as its factorization.

30113102083 is an odious number, because the sum of its binary digits is odd.

The product of its (nonzero) digits is 432, while the sum is 22.

Adding to 30113102083 its reverse (38020131103), we get a palindrome (68133233186).

It can be divided in two parts, 301131020 and 83, that added together give a palindrome (301131103).

The spelling of 30113102083 in words is "thirty billion, one hundred thirteen million, one hundred two thousand, eighty-three".