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30114332323 = 831078933629
BaseRepresentation
bin11100000010111101…
…000011111010100011
32212201201102120211121
4130002331003322203
5443133232113243
621500114353111
72114155413145
oct340275037243
985651376747
1030114332323
1111853834659
125a0528b797
132abbc8636a
1416596cac95
15bb3bb01ed
hex702f43ea3

30114332323 has 8 divisors (see below), whose sum is σ = 30480886800. Its totient is φ = 29747866848.

The previous prime is 30114332299. The next prime is 30114332363. The reversal of 30114332323 is 32323341103.

It is a sphenic number, since it is the product of 3 distinct primes.

It is a cyclic number.

It is not a de Polignac number, because 30114332323 - 25 = 30114332291 is a prime.

It is a super-4 number, since 4×301143323234 (a number of 43 digits) contains 4444 as substring. Note that it is a super-d number also for d = 2.

It is not an unprimeable number, because it can be changed into a prime (30114332363) by changing a digit.

It is a polite number, since it can be written in 7 ways as a sum of consecutive naturals, for example, 878673 + ... + 912301.

It is an arithmetic number, because the mean of its divisors is an integer number (3810110850).

Almost surely, 230114332323 is an apocalyptic number.

30114332323 is a deficient number, since it is larger than the sum of its proper divisors (366554477).

30114332323 is a wasteful number, since it uses less digits than its factorization.

30114332323 is an evil number, because the sum of its binary digits is even.

The sum of its prime factors is 44501.

The product of its (nonzero) digits is 3888, while the sum is 25.

Adding to 30114332323 its reverse (32323341103), we get a palindrome (62437673426).

It can be divided in two parts, 3011 and 4332323, that added together give a palindrome (4335334).

The spelling of 30114332323 in words is "thirty billion, one hundred fourteen million, three hundred thirty-two thousand, three hundred twenty-three".

Divisors: 1 83 10789 33629 895487 2791207 362823281 30114332323