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3012113232002 = 27215150945143
BaseRepresentation
bin101011110101001111111…
…100000111000010000010
3101122221210100110012220102
4223311033330013002002
5343322301441411002
610223425024042402
7430421655013220
oct53651774070202
911587710405812
103012113232002
11a61480437216
12407926763402
1318b06c28bbc4
14a5b0398bb10
1553542dcea02
hex2bd4ff07082

3012113232002 has 8 divisors (see below), whose sum is σ = 5163622683456. Its totient is φ = 1290905670852.

The previous prime is 3012113231929. The next prime is 3012113232017. The reversal of 3012113232002 is 2002323112103.

3012113232002 is digitally balanced in base 2, because in such base it contains all the possibile digits an equal number of times.

It is a sphenic number, since it is the product of 3 distinct primes.

It is a super-2 number, since 2×30121132320022 (a number of 26 digits) contains 22 as substring.

It is an unprimeable number.

It is a polite number, since it can be written in 3 ways as a sum of consecutive naturals, for example, 107575472558 + ... + 107575472585.

It is an arithmetic number, because the mean of its divisors is an integer number (645452835432).

Almost surely, 23012113232002 is an apocalyptic number.

3012113232002 is a deficient number, since it is larger than the sum of its proper divisors (2151509451454).

3012113232002 is a wasteful number, since it uses less digits than its factorization.

3012113232002 is an odious number, because the sum of its binary digits is odd.

The sum of its prime factors is 215150945152.

The product of its (nonzero) digits is 432, while the sum is 20.

Adding to 3012113232002 its reverse (2002323112103), we get a palindrome (5014436344105).

The spelling of 3012113232002 in words is "three trillion, twelve billion, one hundred thirteen million, two hundred thirty-two thousand, two".

Divisors: 1 2 7 14 215150945143 430301890286 1506056616001 3012113232002