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30121250001 = 310040416667
BaseRepresentation
bin11100000011010111…
…011100110011010001
32212202012110001002220
4130003113130303101
5443142020000001
621500522531253
72114301254253
oct340327346321
985665401086
1030121250001
1111857729a47
125a07666b29
132ac0538c6b
14165a5abcd3
15bb45c9c36
hex7035dccd1

30121250001 has 4 divisors (see below), whose sum is σ = 40161666672. Its totient is φ = 20080833332.

The previous prime is 30121249981. The next prime is 30121250011. The reversal of 30121250001 is 10005212103.

It is a semiprime because it is the product of two primes, and also a Blum integer, because the two primes are equal to 3 mod 4, and also an emirpimes, since its reverse is a distinct semiprime: 10005212103 = 33335070701.

It is a cyclic number.

It is not a de Polignac number, because 30121250001 - 218 = 30120987857 is a prime.

It is a super-3 number, since 3×301212500013 (a number of 32 digits) contains 333 as substring.

It is not an unprimeable number, because it can be changed into a prime (30121250011) by changing a digit.

It is a polite number, since it can be written in 3 ways as a sum of consecutive naturals, for example, 5020208331 + ... + 5020208336.

It is an arithmetic number, because the mean of its divisors is an integer number (10040416668).

Almost surely, 230121250001 is an apocalyptic number.

It is an amenable number.

30121250001 is a deficient number, since it is larger than the sum of its proper divisors (10040416671).

30121250001 is a wasteful number, since it uses less digits than its factorization.

30121250001 is an evil number, because the sum of its binary digits is even.

The sum of its prime factors is 10040416670.

The product of its (nonzero) digits is 60, while the sum is 15.

Adding to 30121250001 its reverse (10005212103), we get a palindrome (40126462104).

The spelling of 30121250001 in words is "thirty billion, one hundred twenty-one million, two hundred fifty thousand, one".

Divisors: 1 3 10040416667 30121250001