301244042113 has 4 divisors (see below), whose sum is σ = 344278905280. Its totient is φ = 258209178948.

The previous prime is 301244042069. The next prime is 301244042119. The reversal of 301244042113 is 311240442103.

It is a semiprime because it is the product of two primes, and also a Blum integer, because the two primes are equal to 3 mod 4, and also an emirpimes, since its reverse is a distinct semiprime: 311240442103 = 2371 ⋅131269693.

It is not a de Polignac number, because 301244042113 - 2¹⁷ = 301243911041 is a prime.

It is a Duffinian number.

It is not an unprimeable number, because it can be changed into a prime (301244042119) by changing a digit.

It is a polite number, since it can be written in 3 ways as a sum of consecutive naturals, for example, 21517431573 + ... + 21517431586.

It is an arithmetic number, because the mean of its divisors is an integer number (86069726320).

Almost surely, 2^301244042113 is an apocalyptic number.

It is an amenable number.

301244042113 is a deficient number, since it is larger than the sum of its proper divisors (43034863167).

301244042113 is an equidigital number, since it uses as much as digits as its factorization.

301244042113 is an evil number, because the sum of its binary digits is even.

The sum of its prime factors is 43034863166.

The product of its (nonzero) digits is 2304, while the sum is 25.

Adding to 301244042113 its reverse (311240442103), we get a palindrome (612484484216).

The spelling of 301244042113 in words is "three hundred one billion, two hundred forty-four million, forty-two thousand, one hundred thirteen".