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3013322312113 is a prime number
BaseRepresentation
bin101011110110011000000…
…000011000100110110001
3101200001220121112212000021
4223312120000120212301
5343332241002441423
610224145014523441
7430463636020141
oct53663000304661
911601817485007
103013322312113
11a61a40984a83
12408003666581
1318b202912319
14a5bba3a2921
15535b411095d
hex2bd980189b1

3013322312113 has 2 divisors, whose sum is σ = 3013322312114. Its totient is φ = 3013322312112.

The previous prime is 3013322312083. The next prime is 3013322312149. The reversal of 3013322312113 is 3112132233103.

It is a weak prime.

It can be written as a sum of positive squares in only one way, i.e., 2401099004304 + 612223307809 = 1549548^2 + 782447^2 .

It is an emirp because it is prime and its reverse (3112132233103) is a distict prime.

It is a cyclic number.

It is not a de Polignac number, because 3013322312113 - 217 = 3013322181041 is a prime.

It is a super-2 number, since 2×30133223121132 (a number of 26 digits) contains 22 as substring.

It is not a weakly prime, because it can be changed into another prime (3013322312813) by changing a digit.

It is a polite number, since it can be written as a sum of consecutive naturals, namely, 1506661156056 + 1506661156057.

It is an arithmetic number, because the mean of its divisors is an integer number (1506661156057).

Almost surely, 23013322312113 is an apocalyptic number.

It is an amenable number.

3013322312113 is a deficient number, since it is larger than the sum of its proper divisors (1).

3013322312113 is an equidigital number, since it uses as much as digits as its factorization.

3013322312113 is an evil number, because the sum of its binary digits is even.

The product of its (nonzero) digits is 1944, while the sum is 25.

Adding to 3013322312113 its reverse (3112132233103), we get a palindrome (6125454545216).

The spelling of 3013322312113 in words is "three trillion, thirteen billion, three hundred twenty-two million, three hundred twelve thousand, one hundred thirteen".