3014051113 has 4 divisors (see below), whose sum is σ = 3117983940. Its totient is φ = 2910118288.

The previous prime is 3014051107. The next prime is 3014051141. The reversal of 3014051113 is 3111504103.

3014051113 is digitally balanced in base 2, because in such base it contains all the possibile digits an equal number of times.

It is a semiprime because it is the product of two primes, and also an emirpimes, since its reverse is a distinct semiprime: 3111504103 = 3943 ⋅789121.

It can be written as a sum of positive squares in 2 ways, for example, as 861833449 + 2152217664 = 29357^2 + 46392^2 .

It is a cyclic number.

It is a de Polignac number, because none of the positive numbers 2^k-3014051113 is a prime.

It is a super-2 number, since 2×3014051113² = 18169008223553077538, which contains 22 as substring.

It is a Duffinian number.

It is not an unprimeable number, because it can be changed into a prime (3014051143) by changing a digit.

It is a polite number, since it can be written in 3 ways as a sum of consecutive naturals, for example, 51966370 + ... + 51966427.

It is an arithmetic number, because the mean of its divisors is an integer number (779495985).

Almost surely, 2^3014051113 is an apocalyptic number.

It is an amenable number.

3014051113 is a deficient number, since it is larger than the sum of its proper divisors (103932827).

3014051113 is a wasteful number, since it uses less digits than its factorization.

3014051113 is an evil number, because the sum of its binary digits is even.

The sum of its prime factors is 103932826.

The product of its (nonzero) digits is 180, while the sum is 19.

The square root of 3014051113 is about 54900.3744340601. The cubic root of 3014051113 is about 1444.4977541966.

Adding to 3014051113 its reverse (3111504103), we get a palindrome (6125555216).

The spelling of 3014051113 in words is "three billion, fourteen million, fifty-one thousand, one hundred thirteen".