Base | Representation |
---|---|
bin | 1101101101001110100100… |
… | …01000110011101000000011 |
3 | 10221201110222210100101000110 |
4 | 12312213102020303220003 |
5 | 12422313401111240003 |
6 | 144034421021122403 |
7 | 6230431533406452 |
oct | 666472210635003 |
9 | 127643883311013 |
10 | 30141311040003 |
11 | 9670949332a29 |
12 | 34697080b9403 |
13 | 13a840c803257 |
14 | 762bc0b70b99 |
15 | 3740a0b6ba03 |
hex | 1b69d2233a03 |
30141311040003 has 4 divisors (see below), whose sum is σ = 40188414720008. Its totient is φ = 20094207360000.
The previous prime is 30141311039977. The next prime is 30141311040067. The reversal of 30141311040003 is 30004011314103.
It is a semiprime because it is the product of two primes.
It is not a de Polignac number, because 30141311040003 - 25 = 30141311039971 is a prime.
It is a Duffinian number.
It is not an unprimeable number, because it can be changed into a prime (30141311040083) by changing a digit.
It is a polite number, since it can be written in 3 ways as a sum of consecutive naturals, for example, 5023551839998 + ... + 5023551840003.
It is an arithmetic number, because the mean of its divisors is an integer number (10047103680002).
Almost surely, 230141311040003 is an apocalyptic number.
30141311040003 is a deficient number, since it is larger than the sum of its proper divisors (10047103680005).
30141311040003 is a wasteful number, since it uses less digits than its factorization.
30141311040003 is an odious number, because the sum of its binary digits is odd.
The sum of its prime factors is 10047103680004.
The product of its (nonzero) digits is 432, while the sum is 21.
Adding to 30141311040003 its reverse (30004011314103), we get a palindrome (60145322354106).
The spelling of 30141311040003 in words is "thirty trillion, one hundred forty-one billion, three hundred eleven million, forty thousand, three".
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