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3015404114113 = 5951108544307
BaseRepresentation
bin101011111000010100000…
…101110101000011000001
3101200021021200211100111001
4223320110011311003001
5343401021423122423
610225131343052001
7430566345031546
oct53702405650301
911607250740431
103015404114113
11a6290a0136a6
124084a48a1001
1318b474ccb021
14a5d36a72bcd
1553686c80cad
hex2be141750c1

3015404114113 has 4 divisors (see below), whose sum is σ = 3066512658480. Its totient is φ = 2964295569748.

The previous prime is 3015404114111. The next prime is 3015404114117. The reversal of 3015404114113 is 3114114045103.

It is a semiprime because it is the product of two primes, and also a Blum integer, because the two primes are equal to 3 mod 4.

It is a cyclic number.

It is not a de Polignac number, because 3015404114113 - 21 = 3015404114111 is a prime.

It is a Duffinian number.

It is not an unprimeable number, because it can be changed into a prime (3015404114111) by changing a digit.

It is a polite number, since it can be written in 3 ways as a sum of consecutive naturals, for example, 25554272095 + ... + 25554272212.

It is an arithmetic number, because the mean of its divisors is an integer number (766628164620).

Almost surely, 23015404114113 is an apocalyptic number.

It is an amenable number.

3015404114113 is a deficient number, since it is larger than the sum of its proper divisors (51108544367).

3015404114113 is an equidigital number, since it uses as much as digits as its factorization.

3015404114113 is an evil number, because the sum of its binary digits is even.

The sum of its prime factors is 51108544366.

The product of its (nonzero) digits is 2880, while the sum is 28.

Adding to 3015404114113 its reverse (3114114045103), we get a palindrome (6129518159216).

The spelling of 3015404114113 in words is "three trillion, fifteen billion, four hundred four million, one hundred fourteen thousand, one hundred thirteen".

Divisors: 1 59 51108544307 3015404114113