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30165000793 = 49996034207
BaseRepresentation
bin11100000101111110…
…010110001001011001
32212212020202210220121
4130011332112021121
5443234220011133
621505124353241
72115342163504
oct340576261131
985766683817
1030165000793
111187a3a1624
125a1a245821
132ac9616ac5
14166231a13b
15bb836d02d
hex705f96259

30165000793 has 4 divisors (see below), whose sum is σ = 30171040000. Its totient is φ = 30158961588.

The previous prime is 30165000781. The next prime is 30165000839. The reversal of 30165000793 is 39700056103.

It is a semiprime because it is the product of two primes, and also a Blum integer, because the two primes are equal to 3 mod 4, and also an emirpimes, since its reverse is a distinct semiprime: 39700056103 = 192089476637.

It is a cyclic number.

It is not a de Polignac number, because 30165000793 - 213 = 30164992601 is a prime.

It is a super-4 number, since 4×301650007934 (a number of 43 digits) contains 4444 as substring.

It is a Duffinian number.

It is not an unprimeable number, because it can be changed into a prime (30165000713) by changing a digit.

It is a polite number, since it can be written in 3 ways as a sum of consecutive naturals, for example, 3012105 + ... + 3022102.

It is an arithmetic number, because the mean of its divisors is an integer number (7542760000).

Almost surely, 230165000793 is an apocalyptic number.

It is an amenable number.

30165000793 is a deficient number, since it is larger than the sum of its proper divisors (6039207).

30165000793 is an equidigital number, since it uses as much as digits as its factorization.

30165000793 is an evil number, because the sum of its binary digits is even.

The sum of its prime factors is 6039206.

The product of its (nonzero) digits is 17010, while the sum is 34.

Adding to 30165000793 its reverse (39700056103), we get a palindrome (69865056896).

The spelling of 30165000793 in words is "thirty billion, one hundred sixty-five million, seven hundred ninety-three", and thus it is an aban number.

Divisors: 1 4999 6034207 30165000793