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3020043134113 is a prime number
BaseRepresentation
bin101011111100101000100…
…110010010010010100001
3101200201020222221222120121
4223330220212102102201
5343440022020242423
610231215541240241
7431122325041315
oct53745046222241
911621228858517
103020043134113
11a6487a687025
1240937a403081
1318ba3412aa85
14a6256c09b45
155385918045d
hex2bf289924a1

3020043134113 has 2 divisors, whose sum is σ = 3020043134114. Its totient is φ = 3020043134112.

The previous prime is 3020043134107. The next prime is 3020043134167. The reversal of 3020043134113 is 3114313400203.

It is a weak prime.

It can be written as a sum of positive squares in only one way, i.e., 2745228138129 + 274814995984 = 1656873^2 + 524228^2 .

It is an emirp because it is prime and its reverse (3114313400203) is a distict prime.

It is a cyclic number.

It is not a de Polignac number, because 3020043134113 - 241 = 821019878561 is a prime.

It is not a weakly prime, because it can be changed into another prime (3020043134513) by changing a digit.

It is a pernicious number, because its binary representation contains a prime number (19) of ones.

It is a polite number, since it can be written as a sum of consecutive naturals, namely, 1510021567056 + 1510021567057.

It is an arithmetic number, because the mean of its divisors is an integer number (1510021567057).

Almost surely, 23020043134113 is an apocalyptic number.

It is an amenable number.

3020043134113 is a deficient number, since it is larger than the sum of its proper divisors (1).

3020043134113 is an equidigital number, since it uses as much as digits as its factorization.

3020043134113 is an odious number, because the sum of its binary digits is odd.

The product of its (nonzero) digits is 2592, while the sum is 25.

Adding to 3020043134113 its reverse (3114313400203), we get a palindrome (6134356534316).

The spelling of 3020043134113 in words is "three trillion, twenty billion, forty-three million, one hundred thirty-four thousand, one hundred thirteen".