Base | Representation |
---|---|
bin | 101011111101110110000… |
… | …101010100000000011001 |
3 | 101200211121121002202200201 |
4 | 223331312011110000121 |
5 | 344000202314110431 |
6 | 10231552540302201 |
7 | 431166461504035 |
oct | 53756605240031 |
9 | 11624547082621 |
10 | 3021343113241 |
11 | a6538746a642 |
12 | 409681841961 |
13 | 18bbb05593ab |
14 | a633b7231c5 |
15 | 538d3369461 |
hex | 2bf76154019 |
3021343113241 has 2 divisors, whose sum is σ = 3021343113242. Its totient is φ = 3021343113240.
The previous prime is 3021343113227. The next prime is 3021343113277. The reversal of 3021343113241 is 1423113431203.
3021343113241 is digitally balanced in base 3, because in such base it contains all the possibile digits an equal number of times.
It is a weak prime.
It can be written as a sum of positive squares in only one way, i.e., 2737684614025 + 283658499216 = 1654595^2 + 532596^2 .
It is a cyclic number.
It is not a de Polignac number, because 3021343113241 - 25 = 3021343113209 is a prime.
It is not a weakly prime, because it can be changed into another prime (3021343113941) by changing a digit.
It is a polite number, since it can be written as a sum of consecutive naturals, namely, 1510671556620 + 1510671556621.
It is an arithmetic number, because the mean of its divisors is an integer number (1510671556621).
Almost surely, 23021343113241 is an apocalyptic number.
It is an amenable number.
3021343113241 is a deficient number, since it is larger than the sum of its proper divisors (1).
3021343113241 is an equidigital number, since it uses as much as digits as its factorization.
3021343113241 is an evil number, because the sum of its binary digits is even.
The product of its (nonzero) digits is 5184, while the sum is 28.
Adding to 3021343113241 its reverse (1423113431203), we get a palindrome (4444456544444).
The spelling of 3021343113241 in words is "three trillion, twenty-one billion, three hundred forty-three million, one hundred thirteen thousand, two hundred forty-one".
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