Base | Representation |
---|---|
bin | 1101101111100011000001… |
… | …10000011101111101001010 |
3 | 10222000002201101001021011202 |
4 | 12313301200300131331022 |
5 | 12430120113340304002 |
6 | 144135201455224202 |
7 | 6236252610611663 |
oct | 667614060357512 |
9 | 128002641037152 |
10 | 30221013213002 |
11 | 96a172910a197 |
12 | 3481050218062 |
13 | 13b2aa201b371 |
14 | 7669c214036a |
15 | 3761b7e0a502 |
hex | 1b7c60c1df4a |
30221013213002 has 4 divisors (see below), whose sum is σ = 45331519819506. Its totient is φ = 15110506606500.
The previous prime is 30221013212993. The next prime is 30221013213023. The reversal of 30221013213002 is 20031231012203.
It is a semiprime because it is the product of two primes.
It can be written as a sum of positive squares in only one way, i.e., 25353249110401 + 4867764102601 = 5035201^2 + 2206301^2 .
It is a super-3 number, since 3×302210132130023 (a number of 41 digits) contains 333 as substring.
It is an unprimeable number.
It is a polite number, since it can be written as a sum of consecutive naturals, namely, 7555253303249 + ... + 7555253303252.
Almost surely, 230221013213002 is an apocalyptic number.
30221013213002 is a deficient number, since it is larger than the sum of its proper divisors (15110506606504).
30221013213002 is a wasteful number, since it uses less digits than its factorization.
30221013213002 is an evil number, because the sum of its binary digits is even.
The sum of its prime factors is 15110506606503.
The product of its (nonzero) digits is 432, while the sum is 20.
Adding to 30221013213002 its reverse (20031231012203), we get a palindrome (50252244225205).
The spelling of 30221013213002 in words is "thirty trillion, two hundred twenty-one billion, thirteen million, two hundred thirteen thousand, two".
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