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30221013213002 = 215110506606501
BaseRepresentation
bin1101101111100011000001…
…10000011101111101001010
310222000002201101001021011202
412313301200300131331022
512430120113340304002
6144135201455224202
76236252610611663
oct667614060357512
9128002641037152
1030221013213002
1196a172910a197
123481050218062
1313b2aa201b371
147669c214036a
153761b7e0a502
hex1b7c60c1df4a

30221013213002 has 4 divisors (see below), whose sum is σ = 45331519819506. Its totient is φ = 15110506606500.

The previous prime is 30221013212993. The next prime is 30221013213023. The reversal of 30221013213002 is 20031231012203.

It is a semiprime because it is the product of two primes.

It can be written as a sum of positive squares in only one way, i.e., 25353249110401 + 4867764102601 = 5035201^2 + 2206301^2 .

It is a super-3 number, since 3×302210132130023 (a number of 41 digits) contains 333 as substring.

It is an unprimeable number.

It is a polite number, since it can be written as a sum of consecutive naturals, namely, 7555253303249 + ... + 7555253303252.

Almost surely, 230221013213002 is an apocalyptic number.

30221013213002 is a deficient number, since it is larger than the sum of its proper divisors (15110506606504).

30221013213002 is a wasteful number, since it uses less digits than its factorization.

30221013213002 is an evil number, because the sum of its binary digits is even.

The sum of its prime factors is 15110506606503.

The product of its (nonzero) digits is 432, while the sum is 20.

Adding to 30221013213002 its reverse (20031231012203), we get a palindrome (50252244225205).

The spelling of 30221013213002 in words is "thirty trillion, two hundred twenty-one billion, thirteen million, two hundred thirteen thousand, two".

Divisors: 1 2 15110506606501 30221013213002