Base | Representation |
---|---|
bin | 1101110001111101101011… |
… | …10010010010111010100011 |
3 | 10222022001000221101002012212 |
4 | 12320332311302102322203 |
5 | 12433000140244242201 |
6 | 144241252524112335 |
7 | 6245252315032052 |
oct | 670766562227243 |
9 | 128261027332185 |
10 | 30304044134051 |
11 | 97239669860a6 |
12 | 34951630956ab |
13 | 13ba87507298c |
14 | 76aa1b650399 |
15 | 378427529abb |
hex | 1b8fb5c92ea3 |
30304044134051 has 2 divisors, whose sum is σ = 30304044134052. Its totient is φ = 30304044134050.
The previous prime is 30304044134011. The next prime is 30304044134059. The reversal of 30304044134051 is 15043144040303.
It is a strong prime.
It is a cyclic number.
It is a de Polignac number, because none of the positive numbers 2k-30304044134051 is a prime.
It is a junction number, because it is equal to n+sod(n) for n = 30304044133999 and 30304044134017.
It is not a weakly prime, because it can be changed into another prime (30304044134059) by changing a digit.
It is a polite number, since it can be written as a sum of consecutive naturals, namely, 15152022067025 + 15152022067026.
It is an arithmetic number, because the mean of its divisors is an integer number (15152022067026).
Almost surely, 230304044134051 is an apocalyptic number.
30304044134051 is a deficient number, since it is larger than the sum of its proper divisors (1).
30304044134051 is an equidigital number, since it uses as much as digits as its factorization.
30304044134051 is an evil number, because the sum of its binary digits is even.
The product of its (nonzero) digits is 34560, while the sum is 32.
Adding to 30304044134051 its reverse (15043144040303), we get a palindrome (45347188174354).
The spelling of 30304044134051 in words is "thirty trillion, three hundred four billion, forty-four million, one hundred thirty-four thousand, fifty-one".
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