Base | Representation |
---|---|
bin | 101100001001101010111… |
… | …001110010000100010001 |
3 | 101202001101111100221211221 |
4 | 230021222321302010101 |
5 | 344202203323140103 |
6 | 10241452520205041 |
7 | 432126231151426 |
oct | 54115271620421 |
9 | 11661344327757 |
10 | 3034040443153 |
11 | a6a802807525 |
12 | 410026009781 |
13 | 190155006b65 |
14 | a6bc3bc1d4d |
15 | 53dc7e311bd |
hex | 2c26ae72111 |
3034040443153 has 4 divisors (see below), whose sum is σ = 3034654253568. Its totient is φ = 3033426632740.
The previous prime is 3034040443111. The next prime is 3034040443207. The reversal of 3034040443153 is 3513440404303.
It is a semiprime because it is the product of two primes, and also a Blum integer, because the two primes are equal to 3 mod 4.
It is a cyclic number.
It is not a de Polignac number, because 3034040443153 - 225 = 3034006888721 is a prime.
It is a Duffinian number.
It is not an unprimeable number, because it can be changed into a prime (3034040443103) by changing a digit.
It is a polite number, since it can be written in 3 ways as a sum of consecutive naturals, for example, 306897793 + ... + 306907678.
It is an arithmetic number, because the mean of its divisors is an integer number (758663563392).
Almost surely, 23034040443153 is an apocalyptic number.
It is an amenable number.
3034040443153 is a deficient number, since it is larger than the sum of its proper divisors (613810415).
3034040443153 is an equidigital number, since it uses as much as digits as its factorization.
3034040443153 is an evil number, because the sum of its binary digits is even.
The sum of its prime factors is 613810414.
The product of its (nonzero) digits is 103680, while the sum is 34.
Adding to 3034040443153 its reverse (3513440404303), we get a palindrome (6547480847456).
The spelling of 3034040443153 in words is "three trillion, thirty-four billion, forty million, four hundred forty-three thousand, one hundred fifty-three".
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