Base | Representation |
---|---|
bin | 1101110100110011010011… |
… | …10001111100011100011001 |
3 | 10222122100201111220221200111 |
4 | 12322121221301330130121 |
5 | 12441044340111041101 |
6 | 144354140350204321 |
7 | 6255303554430415 |
oct | 672315161743431 |
9 | 128570644827614 |
10 | 30401553221401 |
11 | 97612542546aa |
12 | 34b00367b36a1 |
13 | 13c6b147b52bb |
14 | 77162b947d45 |
15 | 37ac32c31251 |
hex | 1ba669c7c719 |
30401553221401 has 4 divisors (see below), whose sum is σ = 30402315453312. Its totient is φ = 30400790989492.
The previous prime is 30401553221399. The next prime is 30401553221461. The reversal of 30401553221401 is 10412235510403.
It is a semiprime because it is the product of two primes, and also a Blum integer, because the two primes are equal to 3 mod 4.
It is a cyclic number.
It is not a de Polignac number, because 30401553221401 - 21 = 30401553221399 is a prime.
It is a Duffinian number.
It is not an unprimeable number, because it can be changed into a prime (30401553221461) by changing a digit.
It is a polite number, since it can be written in 3 ways as a sum of consecutive naturals, for example, 381056125 + ... + 381135898.
It is an arithmetic number, because the mean of its divisors is an integer number (7600578863328).
Almost surely, 230401553221401 is an apocalyptic number.
It is an amenable number.
30401553221401 is a deficient number, since it is larger than the sum of its proper divisors (762231911).
30401553221401 is an equidigital number, since it uses as much as digits as its factorization.
30401553221401 is an odious number, because the sum of its binary digits is odd.
The sum of its prime factors is 762231910.
The product of its (nonzero) digits is 14400, while the sum is 31.
Adding to 30401553221401 its reverse (10412235510403), we get a palindrome (40813788731804).
The spelling of 30401553221401 in words is "thirty trillion, four hundred one billion, five hundred fifty-three million, two hundred twenty-one thousand, four hundred one".
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