Base | Representation |
---|---|
bin | 100010100100001001011111… |
… | …0001010101001100110100100 |
3 | 1110212111111100021110012200010 |
4 | 1011020102332022221212210 |
5 | 304322303331331142012 |
6 | 2554343523242450220 |
7 | 121016554016515362 |
oct | 10510227612514644 |
9 | 1425444307405603 |
10 | 304035335412132 |
11 | 88969730723235 |
12 | 2a124102803970 |
13 | 10085541a7052c |
14 | 5511562a32632 |
15 | 25239cba50c3c |
hex | 11484be2a99a4 |
304035335412132 has 96 divisors (see below), whose sum is σ = 717497179001344. Its totient is φ = 100192901529600.
The previous prime is 304035335412119. The next prime is 304035335412139. The reversal of 304035335412132 is 231214533530403.
It is a super-3 number, since 3×3040353354121323 (a number of 44 digits) contains 333 as substring.
It is not an unprimeable number, because it can be changed into a prime (304035335412139) by changing a digit.
It is a polite number, since it can be written in 31 ways as a sum of consecutive naturals, for example, 7490195157 + ... + 7490235747.
Almost surely, 2304035335412132 is an apocalyptic number.
It is an amenable number.
304035335412132 is an abundant number, since it is smaller than the sum of its proper divisors (413461843589212).
It is a pseudoperfect number, because it is the sum of a subset of its proper divisors.
304035335412132 is a wasteful number, since it uses less digits than its factorization.
304035335412132 is an odious number, because the sum of its binary digits is odd.
The sum of its prime factors is 47429 (or 47427 counting only the distinct ones).
The product of its (nonzero) digits is 388800, while the sum is 39.
Adding to 304035335412132 its reverse (231214533530403), we get a palindrome (535249868942535).
The spelling of 304035335412132 in words is "three hundred four trillion, thirty-five billion, three hundred thirty-five million, four hundred twelve thousand, one hundred thirty-two".
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